easy 10 pts Solved

1-Bit Half Adder

The building block behind every adder chain: add two single bits and produce a sum and a carry-out.

Verilog problems / Combinational Design

What you must build

The building block behind every adder chain: add two single bits and produce a sum and a carry-out.

Engineers use “1-Bit Half Adder” as a building block in combinational design. Interviewers ask for the same ports and the same corner cases this judge covers. Completing it in the browser is the same skill as writing synthesizable RTL at work, minus the EDA license.

Concept: sum = a ^ b and cout = a & b. XOR gives the sum because it is 1 exactly when the bits differ; AND gives the carry because a carry only occurs when both bits are 1.

Port contract

The judge instantiates exactly these ports. Extra ports or a different module name fail to elaborate.

NameDirWidthDescription
ainput1First operand bit
binput1Second operand bit
sumoutput1a + b, low bit
coutoutput1Carry out of this bit position

How to approach this kata

This is an introductory kata. Prefer a clear continuous assignment or a small combinational always block. Name the module top_module and keep the port list identical to the table — the hidden testbench instantiates that name.

Hidden tests instantiate top_module, drive the ports, and compare every sample against a golden model. They do not grade coding style. They do grade X/Z, off-by-one counters, and ignoring enables. Sign in only when you want the run saved on the leaderboard — the specification below is public.

Starter shape

Copy this skeleton into the editor (or press Reset starter). Fill the body; do not rename the module.

module top_module(
  input  a,
  input  b,
  output sum,
  output cout
);

  // Your code here

endmodule

Why this shows up in interviews

1-Bit Half Adder sits under Combinational Design (combinational, adder). Concept: sum = a ^ b and cout = a & b . XOR gives the sum because it is 1 exactly when the bits differ; AND gives the carry because a carry only occurs when both bits are 1.

A passing solution is synthesizable intent: no delays in the DUT, no initial blocks inside top_module, and no reference to testbench tasks. Use blocking assignments only in combinational always blocks; use non-blocking for registers clocked by clk.

Related problems

  • 2-to-1 Multiplexer — Select between two 1-bit inputs using sel. When sel=0 output a; when sel=1 output b.
  • 1-Bit Full Adder — Compute sum and carry-out for a + b + cin.
  • 4-to-1 Multiplexer — Select one of four 1-bit inputs using a 2-bit sel. sel=00→in0, 01→in1, 10→in2, 11→in3.
  • 4-to-2 Priority Encoder — Output the index of the highest-priority (MSB-most) set bit in a 4-bit input, plus a valid flag when any bit is set.

FAQ

What does this problem require?

What does the 1-Bit Half Adder problem ask for? The building block behind every adder chain: add two single bits and produce a sum and a carry-out. Implement it as Verilog module top_module with the listed ports.

Combinational or sequential?

Is 1-Bit Half Adder combinational or sequential? Tags: combinational, adder. Follow the clock/reset ports if they appear in the table; if there is no clock, use continuous assignment or combinational always @(*).

How does the auto-grader work?

How is 1-Bit Half Adder graded? A hidden SystemVerilog/Verilog testbench in the EcrioniX judge simulates your module in the browser. You pass when every directed vector matches, including the waveform contract shown on this page.

Write a module named top_module matching the ports below exactly.
Expected waveform
Your solution
Judge output
// Output appears after you run tests.