Part of Curriculum: Sequential RTL Design (Module 5: Decade & Modulo Counters)
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Level 2 Medium ★ Flagship #16 25 pts ✓ Solved

Modulo-10 Counter — Terminal Count

Sequential Logic · sequential, fsm, counters, medium, counters

Design a Modulo-10 (Decade) counter counting from 0 to 9 with active-low async reset. Roll over from 9 to 0.

Write a synthesizable Verilog module named top_module matching the ports below exactly.
📐 Circuit Schematic Diagram
inq[3:0]>clkrst_nMODULO-10 COUNTERSEQUENTIAL COUNTER
⚡ Timing & Synthesizability Constraints

Timing Contract: When q reaches 9 (4'd9), the next active clock edge resets q to 0.

RTL Constraints: Count sequence must be strictly 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 0...

Objective: Understand terminal count detection, state wrapping at arbitrary thresholds, and BCD digit counting.

Prerequisites: Binary counters, equality comparison in sequential blocks.
NameDirWidthDescription
clkinput1Clock signal
areset_ninput1Active-low asynchronous reset
qoutput4Decade count value (0 to 9)
Expected Waveform (Golden Timing Contract)
💡 Need Guidance? Progressive Hints (3 Levels)
Hint 1: Conceptual Direction & Hardware Primitives
Check if `q == 4'd9`: if true, assign `q <= 4'd0;`.
Hint 2: Implementation Architecture & Approach
Otherwise, increment: `q <= q + 1'b1;`.
Hint 3: Edge Cases, Timing & Verilog Syntax
Modulo-10 counters form the core of digital clocks and 7-segment BCD display drivers.
🔒 Reveal Verified Reference RTL Solution (Click to expand)
⚠️ Self-Discovery Warning: Try solving and simulating first! Viewing the verified reference implementation will bypass the real debugging experience.
Verified Synthesizable RTL
module top_module(
  input        clk,
  input        areset_n,
  output reg [3:0] q
);
  always @(posedge clk or negedge areset_n) begin
    if (!areset_n)
      q <= 4'd0;
    else if (q == 4'd9)
      q <= 4'd0;
    else
      q <= q + 1'b1;
  end
endmodule
Verilog-2001 / SV Saved
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Simulation Timing Diagram (VCD Waveform)
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RTL Problems / Level 2 · Sequential Logic

What You Will Learn

By solving Modulo-10 Counter — Terminal Count, you will acquire core industry skills:

  • Synthesizable hardware modeling in standard Verilog-2001 / SystemVerilog.
  • Correct handling of interface port contracts, edge-triggered clocks, and active-low/high resets.
  • Simulation waveform interpretation and debugging using timing diagrams (VCD traces).
  • Architectural avoidance of timing violations, glitching hazards, and synthesis warnings.

Problem Statement & Requirements

Design a Modulo-10 (Decade) counter counting from 0 to 9 with active-low async reset. Roll over from 9 to 0.

Hardware design teams at leading semiconductor firms evaluate these exact port contracts, race-condition assertions, and corner cases during technical design reviews and ASIC engineer interviews.

Objective: Understand terminal count detection, state wrapping at arbitrary thresholds, and BCD digit counting.

Prerequisites: Binary counters, equality comparison in sequential blocks.

Port List & Interface Timing

The hidden testbench instantiates top_module. Module port names and bit-widths must match the interface contract exactly:

NameDirWidthDescription
clkinput1Clock signal
areset_ninput1Active-low asynchronous reset
qoutput4Decade count value (0 to 9)

Timing Constraints & Synthesizable RTL Rules

⚡ Synthesizable Implementation Guidelines

Timing Contract: When q reaches 9 (4'd9), the next active clock edge resets q to 0.

Synthesis Constraints: Count sequence must be strictly 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 0...

Architectural Deep Dive & Implementation Walkthrough

A modulo-$M$ counter resets its state whenever it reaches terminal count $M-1$. In binary-coded decimal (BCD), cascading multiple decade counters creates multi-digit decimal displays (seconds, minutes, hours).

Common RTL Designer Pitfalls

⚠️ Common Mistakes to Avoid

['Checking `if (q == 10)`: this causes the counter to output 10 for one cycle before resetting, making it a modulo-11 counter.', 'Resetting asynchronously on the terminal count, causing severe glitching hazards.']

Silicon & Hardware Engineering Notes

🛠️ ASIC vs FPGA Hardware Considerations

Always perform terminal count reset synchronously (`if (q == 9) q <= 0;`). Asynchronous resets driven by combinational decode logic suffer from transient glitches and race conditions.

Starter RTL Code

module top_module(
  input        clk,
  input        areset_n,
  output reg [3:0] q
);

  // Count from 0 to 9, then wrap back to 0

endmodule

Verified Reference Solution

🔒 Reveal Verified Reference RTL Solution
module top_module(
  input        clk,
  input        areset_n,
  output reg [3:0] q
);
  always @(posedge clk or negedge areset_n) begin
    if (!areset_n)
      q <= 4'd0;
    else if (q == 4'd9)
      q <= 4'd0;
    else
      q <= q + 1'b1;
  end
endmodule

Related RTL Problems in Level 2

Frequently Asked Questions

What does Modulo-10 Counter — Terminal Count require?

Design a Modulo-10 (Decade) counter counting from 0 to 9 with active-low async reset. Roll over from 9 to 0. Implement it as Verilog module top_module matching the listed ports.

Is this design combinational or sequential?

Tags: sequential, fsm, counters, medium, counters. If a clock signal is present in the port table, implement it as sequential logic; otherwise, use continuous assignments or combinational blocks.

How is my solution graded?

A hidden SystemVerilog testbench simulates your module in the cloud judge. You pass when all directed corner cases match the golden model and the VCD timing waveform matches the contract.

How does this challenge help with semiconductor interviews?

Technical interviewers at NVIDIA, Qualcomm, Apple, and Intel routinely ask candidates to code, debug, and explain the timing waveforms of Modulo-10 Counter — Terminal Count to assess real-world synthesizability and race-condition awareness.