Verilog problems / Sequential Design
What you must build
Generate a pulse-width-modulated output with a programmable duty cycle out of 16 — the technique behind LED dimming and motor speed control.
Engineers use “PWM Generator” as a building block in sequential design. Interviewers ask for the same ports and the same corner cases this judge covers. Completing it in the browser is the same skill as writing synthesizable RTL at work, minus the EDA license.
pwm_out = (cnt < duty). The strict less-than matters: using <= instead makes every duty value one cycle wider than requested, breaking duty=0 (which should mean "always off").Port contract
The judge instantiates exactly these ports. Extra ports or a different module name fail to elaborate.
| Name | Dir | Width | Description |
|---|---|---|---|
| clk | input | 1 | Clock |
| rst | input | 1 | Sync active-high reset |
| duty | input | 4 | Duty cycle, 0-15 out of 16 |
| pwm_out | output | 1 | High for duty cycles out of every 16 |
How to approach this kata
This is a medium kata: you will need sequential logic or a small FSM. Decide what is registered versus combinational before you type. Reset polarity and clock edge must match the spec; the judge will fail you on the first mismatched cycle.
Hidden tests instantiate top_module, drive the ports, and compare every sample against a golden model. They do not grade coding style. They do grade X/Z, off-by-one counters, and ignoring enables. Sign in only when you want the run saved on the leaderboard — the specification below is public.
Starter shape
Copy this skeleton into the editor (or press Reset starter). Fill the body; do not rename the module.
module top_module( input clk, input rst, input [3:0] duty, output pwm_out ); // Your code here — free-running 4-bit counter; pwm_out = (cnt < duty). endmodule
Why this shows up in interviews
PWM Generator sits under Sequential Design (sequential, clock). Concept: A free-running 4-bit counter sweeps 0-15 every 16 cycles; the output is simply pwm_out = (cnt < duty) . The strict less-than matters: using <= instead makes every duty value one cycle wider than requested, breaking duty=0 (which should mean "always off").
A passing solution is synthesizable intent: no delays in the DUT, no initial blocks inside top_module, and no reference to testbench tasks. Use blocking assignments only in combinational always blocks; use non-blocking for registers clocked by clk.
Related problems
- D Flip-Flop with Asynchronous Reset — Standard D flip-flop with an active-low asynchronous reset. Reset clears q immediately, without waiting for a clock edge.
- 4-Bit Shift Register (SIPO) — Serial-in, parallel-out shift register. Each clock, shift left and load sin into the LSB. Sync active-high reset clears q.
- JK Flip-Flop — The flip-flop with no forbidden state: j=k=1 toggles instead of racing. Classic building block for counters.
- 4-Bit Up/Down Counter — A synchronous counter that increments or decrements each clock edge depending on a direction input, with a synchronous reset.
FAQ
What does this problem require?
What does the PWM Generator problem ask for? Generate a pulse-width-modulated output with a programmable duty cycle out of 16 — the technique behind LED dimming and motor speed control. Implement it as Verilog module top_module with the listed ports.
Combinational or sequential?
Is PWM Generator combinational or sequential? Tags: sequential, clock. Follow the clock/reset ports if they appear in the table; if there is no clock, use continuous assignment or combinational always @(*).
How does the auto-grader work?
How is PWM Generator graded? A hidden SystemVerilog/Verilog testbench in the EcrioniX judge simulates your module in the browser. You pass when every directed vector matches, including the waveform contract shown on this page.