easy 10 pts Solved

Synchronous 8x8 RAM

A minimal single-port RAM: 8 words of 8 bits each, with a registered (one-cycle-delayed) read — the standard timing behavior of real block RAM.

Verilog problems / Sequential Design

What you must build

A minimal single-port RAM: 8 words of 8 bits each, with a registered (one-cycle-delayed) read — the standard timing behavior of real block RAM.

Engineers use “Synchronous 8x8 RAM” as a building block in sequential design. Interviewers ask for the same ports and the same corner cases this judge covers. Completing it in the browser is the same skill as writing synthesizable RTL at work, minus the EDA license.

Concept: The write is a simple if(we) mem[addr]<=din;. The read is what trips people up: dout<=mem[addr]; is a registered read — it captures the addressed word one cycle late, matching how real synchronous RAM behaves. Making dout a combinational assign instead gives zero-cycle latency, a different (and usually wrong) timing contract for anything expecting real memory behavior.

Port contract

The judge instantiates exactly these ports. Extra ports or a different module name fail to elaborate.

NameDirWidthDescription
clkinput1Clock
weinput1Write enable
addrinput3Address, 0-7
dininput8Write data
doutoutput8Registered read data (1-cycle latency)

How to approach this kata

This is a medium kata: you will need sequential logic or a small FSM. Decide what is registered versus combinational before you type. Reset polarity and clock edge must match the spec; the judge will fail you on the first mismatched cycle.

Hidden tests instantiate top_module, drive the ports, and compare every sample against a golden model. They do not grade coding style. They do grade X/Z, off-by-one counters, and ignoring enables. Sign in only when you want the run saved on the leaderboard — the specification below is public.

Starter shape

Copy this skeleton into the editor (or press Reset starter). Fill the body; do not rename the module.

module top_module(
  input      clk,
  input      we,
  input      [2:0] addr,
  input      [7:0] din,
  output reg [7:0] dout
);

  // Your code here — reg [7:0] mem [0:7]; write on we, and register dout <= mem[addr] every cycle.

endmodule

Why this shows up in interviews

Synchronous 8x8 RAM sits under Sequential Design (sequential, memory). Concept: The write is a simple if(we) mem[addr]<=din; . The read is what trips people up: dout<=mem[addr]; is a registered read — it captures the addressed word one cycle late, matching how real synchronous RAM behaves. Making dout a combinational assign instead gives zero-cycle latency, a different (and usually wrong) timing contract for anything expecting real memory behavior.

A passing solution is synthesizable intent: no delays in the DUT, no initial blocks inside top_module, and no reference to testbench tasks. Use blocking assignments only in combinational always blocks; use non-blocking for registers clocked by clk.

Related problems

  • D Flip-Flop with Asynchronous Reset — Standard D flip-flop with an active-low asynchronous reset. Reset clears q immediately, without waiting for a clock edge.
  • 4-Bit Shift Register (SIPO) — Serial-in, parallel-out shift register. Each clock, shift left and load sin into the LSB. Sync active-high reset clears q.
  • JK Flip-Flop — The flip-flop with no forbidden state: j=k=1 toggles instead of racing. Classic building block for counters.
  • 4-Bit Up/Down Counter — A synchronous counter that increments or decrements each clock edge depending on a direction input, with a synchronous reset.

FAQ

What does this problem require?

What does the Synchronous 8x8 RAM problem ask for? A minimal single-port RAM: 8 words of 8 bits each, with a registered (one-cycle-delayed) read — the standard timing behavior of real block RAM. Implement it as Verilog module top_module with the listed ports.

Combinational or sequential?

Is Synchronous 8x8 RAM combinational or sequential? Tags: sequential, memory. Follow the clock/reset ports if they appear in the table; if there is no clock, use continuous assignment or combinational always @(*).

How does the auto-grader work?

How is Synchronous 8x8 RAM graded? A hidden SystemVerilog/Verilog testbench in the EcrioniX judge simulates your module in the browser. You pass when every directed vector matches, including the waveform contract shown on this page.

Write a module named top_module matching the ports below exactly.
Expected waveform
Your solution
Judge output
// Output appears after you run tests.