easy 10 pts Solved

Modulo-6 Counter

A counter that wraps back to 0 after reaching 5, instead of overflowing at the natural binary boundary — the pattern behind clock dividers and digit counters.

Verilog problems / Sequential Design

What you must build

A counter that wraps back to 0 after reaching 5, instead of overflowing at the natural binary boundary — the pattern behind clock dividers and digit counters.

Engineers use “Modulo-6 Counter” as a building block in sequential design. Interviewers ask for the same ports and the same corner cases this judge covers. Completing it in the browser is the same skill as writing synthesizable RTL at work, minus the EDA license.

Concept: Ordinary counters wrap for free at 2^N. A modulo-6 counter needs an explicit wrap check: if (q == 5) q <= 0; else q <= q + 1; — the comparison must come before the increment in priority, not after.

Port contract

The judge instantiates exactly these ports. Extra ports or a different module name fail to elaborate.

NameDirWidthDescription
clkinput1Clock
rstinput1Sync active-high reset
qoutput3Counts 0 through 5, then wraps

How to approach this kata

This is a medium kata: you will need sequential logic or a small FSM. Decide what is registered versus combinational before you type. Reset polarity and clock edge must match the spec; the judge will fail you on the first mismatched cycle.

Hidden tests instantiate top_module, drive the ports, and compare every sample against a golden model. They do not grade coding style. They do grade X/Z, off-by-one counters, and ignoring enables. Sign in only when you want the run saved on the leaderboard — the specification below is public.

Starter shape

Copy this skeleton into the editor (or press Reset starter). Fill the body; do not rename the module.

module top_module(
  input            clk,
  input            rst,
  output reg [2:0] q
);

  // Your code here

endmodule

Why this shows up in interviews

Modulo-6 Counter sits under Sequential Design (sequential, counter). Concept: Ordinary counters wrap for free at 2^N. A modulo-6 counter needs an explicit wrap check: if (q == 5) q <= 0; else q <= q + 1; — the comparison must come before the increment in priority, not after.

A passing solution is synthesizable intent: no delays in the DUT, no initial blocks inside top_module, and no reference to testbench tasks. Use blocking assignments only in combinational always blocks; use non-blocking for registers clocked by clk.

Related problems

  • D Flip-Flop with Asynchronous Reset — Standard D flip-flop with an active-low asynchronous reset. Reset clears q immediately, without waiting for a clock edge.
  • 4-Bit Shift Register (SIPO) — Serial-in, parallel-out shift register. Each clock, shift left and load sin into the LSB. Sync active-high reset clears q.
  • JK Flip-Flop — The flip-flop with no forbidden state: j=k=1 toggles instead of racing. Classic building block for counters.
  • 4-Bit Up/Down Counter — A synchronous counter that increments or decrements each clock edge depending on a direction input, with a synchronous reset.

FAQ

What does this problem require?

What does the Modulo-6 Counter problem ask for? A counter that wraps back to 0 after reaching 5, instead of overflowing at the natural binary boundary — the pattern behind clock dividers and digit counters. Implement it as Verilog module top_module with the listed ports.

Combinational or sequential?

Is Modulo-6 Counter combinational or sequential? Tags: sequential, counter. Follow the clock/reset ports if they appear in the table; if there is no clock, use continuous assignment or combinational always @(*).

How does the auto-grader work?

How is Modulo-6 Counter graded? A hidden SystemVerilog/Verilog testbench in the EcrioniX judge simulates your module in the browser. You pass when every directed vector matches, including the waveform contract shown on this page.

Write a module named top_module matching the ports below exactly.
Expected waveform
Your solution
Judge output
// Output appears after you run tests.