easy 10 pts Solved

SR Flip-Flop

A set/reset flip-flop with a well-defined answer for the "both asserted" case that the classic SR latch leaves undefined.

Verilog problems / Sequential Design

What you must build

A set/reset flip-flop with a well-defined answer for the "both asserted" case that the classic SR latch leaves undefined.

Engineers use “SR Flip-Flop” as a building block in sequential design. Interviewers ask for the same ports and the same corner cases this judge covers. Completing it in the browser is the same skill as writing synthesizable RTL at work, minus the EDA license.

Concept: Give reset priority: if (r) q<=0; else if (s) q<=1;. Whichever input you check first in the if-chain automatically wins when both are asserted — no invalid/undefined state, unlike a level-sensitive SR latch.

Port contract

The judge instantiates exactly these ports. Extra ports or a different module name fail to elaborate.

NameDirWidthDescription
clkinput1Clock
sinput1Set
rinput1Reset (priority over set)
qoutput1Stored bit

How to approach this kata

This is an introductory kata. Prefer a clear continuous assignment or a small combinational always block. Name the module top_module and keep the port list identical to the table — the hidden testbench instantiates that name.

Hidden tests instantiate top_module, drive the ports, and compare every sample against a golden model. They do not grade coding style. They do grade X/Z, off-by-one counters, and ignoring enables. Sign in only when you want the run saved on the leaderboard — the specification below is public.

Starter shape

Copy this skeleton into the editor (or press Reset starter). Fill the body; do not rename the module.

module top_module(
  input      clk,
  input      s,
  input      r,
  output reg q
);

  // Your code here — give r priority over s.

endmodule

Why this shows up in interviews

SR Flip-Flop sits under Sequential Design (sequential, flip-flop). Concept: Give reset priority: if (r) q<=0; else if (s) q<=1; . Whichever input you check first in the if-chain automatically wins when both are asserted — no invalid/undefined state, unlike a level-sensitive SR latch.

A passing solution is synthesizable intent: no delays in the DUT, no initial blocks inside top_module, and no reference to testbench tasks. Use blocking assignments only in combinational always blocks; use non-blocking for registers clocked by clk.

Related problems

  • D Flip-Flop with Asynchronous Reset — Standard D flip-flop with an active-low asynchronous reset. Reset clears q immediately, without waiting for a clock edge.
  • 4-Bit Shift Register (SIPO) — Serial-in, parallel-out shift register. Each clock, shift left and load sin into the LSB. Sync active-high reset clears q.
  • JK Flip-Flop — The flip-flop with no forbidden state: j=k=1 toggles instead of racing. Classic building block for counters.
  • 4-Bit Up/Down Counter — A synchronous counter that increments or decrements each clock edge depending on a direction input, with a synchronous reset.

FAQ

What does this problem require?

What does the SR Flip-Flop problem ask for? A set/reset flip-flop with a well-defined answer for the &quot;both asserted&quot; case that the classic SR latch leaves undefined. Implement it as Verilog module top_module with the listed ports.

Combinational or sequential?

Is SR Flip-Flop combinational or sequential? Tags: sequential, flip-flop. Follow the clock/reset ports if they appear in the table; if there is no clock, use continuous assignment or combinational always @(*).

How does the auto-grader work?

How is SR Flip-Flop graded? A hidden SystemVerilog/Verilog testbench in the EcrioniX judge simulates your module in the browser. You pass when every directed vector matches, including the waveform contract shown on this page.

Write a module named top_module matching the ports below exactly.
Expected waveform
Your solution
Judge output
// Output appears after you run tests.